Question

sqrt 4a+1 endsqrt +3=2

Answer 1

\[\sqrt{4a+1}+3=2\]?
if so no solution

Answer 2

if you start by subtracting \(3\) you get
\[\sqrt{4a+1}=-1\] and the radical on the left is greater than or equal to zero, so it cannot be \(-1\)

Answer 3

so its a null set correct?