Question

Factor completely: 32c15d14 – 48c5d7

Answer 1

This will be:\[32c ^{15}d^{14}-48c^5d^7\]You will have to look for common factors, i.e. numbers that are dividers of both the terms.
It is not as complicated as it sounds, because you can andle every number separately:
Look at the 32 and 48, the c's and the d's.
16 is a factor of 3e2 and 48, so factor it out.
I see c^5 is also in both terms, so:\[16c^5d^{...}(2c^{10}d^{...}-3d^{...})\]
Try yo fill in the blanks yourself...