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how to solve this root?
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\[\LARGE \frac{1}{\sqrt{1.8 \times 10^{-6}}} \]
@hartnn
root of 1.8 by approximate calculation corresponds to 1.35
use calculator.
im not allowed >.>
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how u got this ? root of 1.8 by approximate calculation corresponds to 1.35
rough mathematics :P 1*1=1 1.2*1.2=1.44 1.3*1.3=1.69 1.4*1.4=1.96 but we need 1.8 so it must lie between 1.3*1.4 so take it as 1.35 (u can check via calculator too thats correct) thats just my way of doing pellet calculations because every second in IIT exam will be worth so i just have to make approx calculations
i cant solve for 10^-6
sqrt (10^(-6)) = 10^(-6)^(1/2) = 10^-3 1/10^-3 = 10^3
so 1000/1.35? :O
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yup.
amazing thanks o.o why didnt i notice that x(
ask yourself.... welcome :)
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