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They look great! Good job
Nice
Sorry, I know its alot :/
Lol :P .
http://assets.openstudy.com/updates/attachments/50ca22a9e4b0a14e43695095-coolaidd-1355424646452-screenshot20121213at1.40.18pm.png Should have the point at 4 not 3.
The rest of it looks fine.
I CANNOT help you on the polar coordinates though as I have not learnt them.
ok how do i figure out 25?
Ohh it's 5^0 ! I thought it said 9 :P .
Then you are correct ^_^ .
ok...soo everything else (besides polar coordinates) are correct??
Yep :) . To me.
thank you soooooo much! :)
You are welcome! :) .
Don't you feel confident enough with your answers?
seems like you've answered them to the best of your ability.
Yes.. but its not about just being confident..I want to be correct
Aren't you going to submit it? :P .
@Dido525 question 14 looks correct for the graph of 1+3i http://assets.openstudy.com/updates/attachments/50ca22a9e4b0a14e43695095-coolaidd-1355424646452-screenshot20121213at1.40.18pm.png
http://assets.openstudy.com/updates/attachments/50ca22a9e4b0a14e43695095-coolaidd-1355424645497-screenshot20121213at1.44.56pm.png Question 4 looks incorrect - there aren't two real roots, there's two conjugate roots (the discriminant is sqrt(-11))
http://assets.openstudy.com/updates/attachments/50ca22a9e4b0a14e43695095-coolaidd-1355424765655-screenshot20121213at1.45.29pm.png for standard form in Q18, you should divide the whole equation by 9 (standard form of an ellipse is = 1) http://assets.openstudy.com/updates/attachments/50ca22a9e4b0a14e43695095-coolaidd-1355424765202-screenshot20121213at1.45.33pm.png for 21, it looks like you only posted the coordinates of one of the foci. The other would be (-2, 3+2sqrt(2)) http://assets.openstudy.com/updates/attachments/50ca22a9e4b0a14e43695095-coolaidd-1355424828452-screenshot20121213at1.45.38pm.png 24, asks for the minor axis vertices, and you've given the major axis vertices. Minor axis vertices should be (-3, 3) and (-1,3) http://assets.openstudy.com/updates/attachments/50ca22a9e4b0a14e43695095-coolaidd-1355424827838-screenshot20121213at1.45.51pm.png 27 should be ln12/ln5, how'd you get ln5/ln10?
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