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Algebra
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Simplify the expression: (3xy)^-1
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Similar problem: \[\Large (7xyz)^{-1} = \frac{1}{(7xyz)^1}\] \[\Large (7xyz)^{-1} = \frac{1}{7xyz}\]
A. - 1 3xy B. -3xy C. 1 3xy D. 3xy
so which one do you think it is based off that example i gave you?
c
yep
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assuming C is \[\Large \frac{1}{3xy}\]
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