Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).

A. y = 1/3x − 3

B. y = 1/3x + 17

C. y = −3x − 3

D. y = −3x + 17

Question

Write the equation of the line that is perpendicular to the line 3x + y = 7 and passes through the point (6, −1).

A.  y = 1/3x − 3 

B. y = 1/3x + 17 

C. y = −3x − 3 

D. y = −3x + 17

anonymous · Answer

Perpendicular lines have slopes that are negative reciprocals. What is the slope of 3x+y=7 ?

anonymous · Answer

the slope is got when you divide -x coefficient on y coefficient.
so the slope is -3 and the slope of peripendicular line is 1/3;
then y-(-1)=1/3(x-6)
so A is true

anonymous · Answer

thanks!