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Mathematics 19 Online
OpenStudy (jennychan12):

Substitution Rule(again...) See below.

OpenStudy (jennychan12):

\[\int\limits (\frac{ x+1 }{ (x^2++2x-3)^2 })dx\]

OpenStudy (bibby):

u=\[x^{2}+2x+3\] du = 2x +x = 2(x+1)

OpenStudy (bibby):

2x + 2*

OpenStudy (raden):

du = 2(x+1)dx 1/2 du =(x+1) dx

OpenStudy (jennychan12):

what i have so far: u = (x^2+2x-3) du = (2x+2)dx dx = du/(2x+2) how do i get x in terms of u?

OpenStudy (jennychan12):

ohh @RadEn i get what u did....

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