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solve x^2 + 2^2 = 0
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x^2=-4 so it doesnt have any answer
so would i leave it x^2=-4?
\(x = \sqrt{-4} = 2i\)
i put x = +/- 2 and got it wrong
@geerky42 thanks, now i remember it
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yes ofcourse in real world of number else it has answer in complex world in this way 2i and -2i
Ah, and -2i. I forgot about plus/minus, lol.
glad we helped, though.
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