Question

evaluate to make a rational number
log5(3√625)−9^(3/2)

5- is the base..

Answer 1

the last part is easiest
\[9^{\frac{3}{2}}=\sqrt{9}^3=3^3=27\]

Answer 2

the first part you can use
\[\frac{1}{3}\log_5(625)=\frac{1}{3}\log_5(5^4)=\frac{4}{3}\]