Write the equation of the line that is parallel to the line 4x − 3y = −12 and passes through the point (−3, 4).

y = four thirdsx + 8

y = four thirdsx + 3

y = −three fourthsx + 8

y = −three fourthsx + 3

Question

Write the equation of the line that is parallel to the line 4x − 3y = −12 and passes through the point (−3, 4).

y = four thirdsx + 8

y = four thirdsx + 3

y = −three fourthsx + 8

y = −three fourthsx + 3

anonymous · Answer

Hei, friend, it hould be you give the question in Mathematics subject, but it is no problem. I will answer it :)
First, find the gradien
4x − 3y = −12 
y = (-4x -12)/3
y = -4x/3  4
It means that the gradien is -4/3 because it is parallel
use the formula to find the equation
y-y1 = m(x - x1)
y - 4 = -4/3 (x +3)
y = -4x/3
So, the equation is y = -4x/3