Question

factor completely
10y^6+34y^5+12y^4

Answer 1

10y^6+34y^5+12y^4

y^4[10y^2+34y+12]

y^4[10y^2+30y+4y+12]

y^4[10y(y+3)+4(y+3)]

y^4[(y+3)(10y+4)]

The final answer is ............y^4*(y+3)*(10y+4)

Answer 2

10y^6 + 34y^5 + 12y^4

Find all the common factors. 2y^4 comes to mind.

2y^4*(5y^2 + 17y + 6)

Hopefully, we can factor that trinomial.

2y^4*(y+3)*(5y+2)

THAT is a COMPLETE factorization.