2t + 3t + 5 = 2t - 3 Grade 9 work. please help me, i beg :(
1) isolate the t's on one side. 2) then subtract and add as usual and find t as usual
i would combine like terms on the left first : \[2t + 3t + 5 = 2t - 3 \] turns in to \[5t+5=2t-3\]
then if you subtract \(2t\) from both sides you will get \[3t+5=-3\] subtract 5 to both sides , get \[3t=-8\] and finally divide both sides by 3 to get \(t=-\frac{8}{3}\)
But Satellite how will we do this? Like your not explaining the (subtract 2t from both sides, subtract 5 to both and the divide both sides by 3)
ok lets start at the end suppose i told you that \(3t=-8\) could you tell me what \(t\) was?
no...
ok lets try an easier one suppose i told you \(3t=12\) what would \(t\) be in this case?
3
yes, and how do you know it? one reason is because \(3\times 4=12\) which is another way of saying \[4=\frac{12}{3}\]
in other words, so solve \(3t=12\) you divide \(12\) by \(3\)
2x + 5x = -9 + 4 4y 6y --- = ---- 2 3 32x + 2 = 4x +3 THESE QUESTIONS HELP
now \(3\) does not go in to \(-8\) evenly, so we don't get a whole number as an answer, but you still divide \(-8\) by \(3\) but in this case you just write the answer as \(-\frac{8}{3}\) without actually dividing
first one \[2x + 5x = -9 + 4 \] what is \(2x+5x\) ?
Ok, now do the other ones. THANKS!
7?
just do it please hurry :(
do all the questions!
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i do want to learn
that site isn't doing anything
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