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Let h and g be two functions defined by h(x)=4x^2-5 g(x)=7x-2 for any real number x . Find h/g(-4) and then find all values that are NOT in the domain of h/g .
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h(x)/g(x) =(4x^2-5)/(7x-2) Now, h/g(-4) =(4(-4)^2 -5) / (7(-4) -2)
Simplify it.
59/26
?
59/(-30)
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damn haha okay now what
Now, h/g is undefined when denominator is 0 SO, find for what value of x the denominator will be 0
@kaelyb can u?
hmm i dont know what it would be!
for what value of x 7x-2 is 0
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Hint: 7x-2=0 Now, solve for x
ohhh gotchu haha 2/7
So, when x=2/7 the denominator is 0. so 2/7 is not in the domain of h/g
okay cool thanks!
welcome
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