Question

y=acos(logx)+bsin(logx)
dy/dx=?

Answer 1

Attempt:
\[\LARGE \frac{dy}{dx}= -asin(\log x) \times \frac{1}{x} +bcos(logx) \times \frac{1}{x}\]

Answer 2

@hartnn

Answer 3

if u have 1/x in the end, then its correct

Answer 4

jo likha wahi hai :o

Answer 5

i can't see the last 1/x

Answer 6

http://gyazo.com/9ead2d18c9ae8027f8e27c572a6ba1f6

Answer 7

\( \frac{dy}{dx}= -asin(\log x) \times \frac{1}{x} +bcos(logx) \times \frac{1}{x}\)

Answer 8

its there and its correct.

Answer 9

:D