Question

Factoring Quadratic Functions

Answer 1

(w+6)^2=3(w+12)-w^2

Answer 2

Now, what I did was...

Answer 3

(w+6)(w+6)
w^2+6w+6w+36
w^2+12w+36

Answer 4

w^2+12w+36 = 3w+36-w^2
+w^2 +w^2
-----------------------------
2w^2+9w=0

Answer 5

Now, I am at a loss of what to do...

Answer 6

I just did a problem like this too....

Answer 7

Factor out a w

Answer 8

w(w+9)

Answer 9

Answer is w=(0,-9/2)

Answer 10

w(w+9)=0 ?

Answer 11

w(2w+9)

then set them both equal to 0

w=0

2w+9=0

Answer 12

lol jk u did good, just messed up a little

Answer 13

Thanks @CalebBeavers