solve the system of equations
x+2y=6
x^2+y^2=8

Question

solve the system of equations 
x+2y=6
x^2+y^2=8

anonymous · Answer

I got 24 plus or minus radical 1136 all over 10 and I feel  like what a I suppose to do with that.

anonymous · Answer

x = 6 - 2y

(6 - 2y)^2 + y^2 = 8

4y^2 -24y + 36 + y ^2 = 8

5y^2 -24y + 36 = 8

5y^2 - 24y + 28 = 0

y = 2
y = 14/5

sub those back in to the linear

anonymous · Answer

I did everything u did but from the last line I went and plugged in the quadratic equation where did u get y=2 and y =14/5?

anonymous · Answer

I still need help, im not understanding this.

anonymous · Answer

solving 5y^2 - 24y + 28 = 0

you get y =  2, 14/5

anonymous · Answer

ya but what do u mean solving that, what did u do to solve it because I tried the quadratic and got this weird number.

anonymous · Answer

solve for the zeroes, what else?

anonymous · Answer

use quad formula, factor, anything you want.

anonymous · Answer

ugh forget it.