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solve the system of equations x+2y=6 x^2+y^2=8
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I got 24 plus or minus radical 1136 all over 10 and I feel like what a I suppose to do with that.
x = 6 - 2y (6 - 2y)^2 + y^2 = 8 4y^2 -24y + 36 + y ^2 = 8 5y^2 -24y + 36 = 8 5y^2 - 24y + 28 = 0 y = 2 y = 14/5 sub those back in to the linear
I did everything u did but from the last line I went and plugged in the quadratic equation where did u get y=2 and y =14/5?
I still need help, im not understanding this.
solving 5y^2 - 24y + 28 = 0 you get y = 2, 14/5
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ya but what do u mean solving that, what did u do to solve it because I tried the quadratic and got this weird number.
solve for the zeroes, what else?
use quad formula, factor, anything you want.
ugh forget it.
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