Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

EMERGENCY PLEASE HELPPPPPPPPPPPPP!!!! :[ ... Will FAN and GIVE MEDAL !!! DESPERATE I know the answer to the first one is 6w^2√2 i just dont know how to show my work A.√(6w^(3)) √(12w) 4. The graph of f (x ) is show below ( cant get a photo but it looks like a normal graph with a 'w' to the left side on the graph) a. On this coordinate plane draw the graph of 1f (x )  . (1 pt) b. Is f (x ) a function? (1pt) c. Is 1f (x )  a function? (1 pt)

OpenStudy (anonymous):

Can you please just type out the exact wording of the problem? 'm having a hard time understanding what exactly you're looking for.

OpenStudy (zehanz):

Thank you for becoming my fan, but I really do not understand what the formula 6w^2√2 is supposed to mean...

OpenStudy (anonymous):

1. Simplify each expression. Show all work, step-by-step. (3 pts each) a. √6w^3 times √12w

OpenStudy (zehanz):

Is it:\[\sqrt{6w^3}*\sqrt{12w}\]

OpenStudy (anonymous):

yes :]

OpenStudy (anonymous):

Simplified: 6 sqrt(2) w^2 (Picture attached with how it looks.)

OpenStudy (anonymous):

OpenStudy (zehanz):

In that case I would write\[\sqrt{72w^4}=\sqrt{36w^4}\sqrt{2}=6w^2\sqrt{2}\](assuming w>=0)

OpenStudy (anonymous):

thank you so much you were both a great help !

OpenStudy (zehanz):

As you can see, if you compare pathosdebaters' answer and mine, there are two ways to write the answer!

OpenStudy (anonymous):

Yeah, both ways work since you can arrange multiplicative devices around with the same results.

OpenStudy (anonymous):

awesome ! thanks so much now i just gotta figure out the last one lol im horrible with graphs

OpenStudy (anonymous):

WHat's the exact wording of the problem?

OpenStudy (anonymous):

4. The graph of f (x ) is show below a. On this coordinate plane draw the graph of 1f (x )  . (1 pt) b. Is f (x ) a function? (1pt) c. Is 1f (x )  a function? (1 pt)

OpenStudy (anonymous):

|dw:1355608353124:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!