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Calculus1 19 Online
OpenStudy (anonymous):

evaluate indefinite integrals intergral tan^2x Sec^2x dx

OpenStudy (anonymous):

tanx=u

OpenStudy (anonymous):

take the derivative

OpenStudy (anonymous):

derivative of tanx?

OpenStudy (anonymous):

both sides

OpenStudy (anonymous):

what is it

OpenStudy (anonymous):

derivative of tna is sec^2x

OpenStudy (anonymous):

sec^2xdx=du

OpenStudy (anonymous):

subs. them in int.

OpenStudy (anonymous):

if tanx=u then what is tan^2x

OpenStudy (anonymous):

u sqre

OpenStudy (anonymous):

good

OpenStudy (anonymous):

then what is your new int. depends on only u

OpenStudy (anonymous):

int. tan^2x Sec^2x dx sec^2xdx=du tan^2x=u^2

OpenStudy (anonymous):

csc x^3/ 3 ?

OpenStudy (anonymous):

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