Question

Center in first quadrant, r=3, tangent to y-axis (0,1)?

Answer 1

first, graph the circle and utilize after that looks the centre of circle is (3,1)

Answer 2

do u want to find an equation of the circle ?

Answer 3

yes, the question about finding equation of the circle; if it becomes (3.1) then the answer must be like this; (x-3)^2+(y-1)^2=3^2
r2=10
the radius=3

is it correct?

Answer 4

the equation of circle be (x-3)^2+(y-1)^2=3^2
u are right ?

Answer 5

Thank you so much.

Answer 6

welcome...
but why, u write r^2 = 10 ? it should be r^2 = 9 right ?