Question

How many solutions (x,y,z) that satisfies xyz=1000 with x,y, and z are positive integer numbers ?

Answer 1

1000 = 2^3 * 5^3 = 2*2*2 *5*5*5 *1
you have to form 3 sets from these 7 elements such that all elements are used.
question is how many such formations are possible such that none is empty set..

Answer 2

each set would represent x,y or z

Answer 3

still confused --"