Question

geometry questions involving arcs and angles!
picture will be posted as a comment

Answer 1

m (arc AB) = 88, so m<AGB = 44, m<AGD = 44
m (arc DG) = 62, so m<5 = 31
m<2 + m<AGB + m<5 = 180
m<2 + 44 + 31 = 180
m<2 = 105
m<1 = 75
m (arc DA) = 2m<AGD = 88
m (arc DA) + m (arc DG) + m (arc GB) + m (arc AB) = 360
88 + 62 + m (arc GB) + 88 = 360
m (arc GB) = 122
m<7 = (1/2)m ( arc GB) = 61
m<7 = 61
m<7 + m<1 + m<6 = 180
61 + 75 + m<6 = 180
m<6 = 44
m<4 = (1/2)(m arc DAB - m arc DG)
m<4 = (1/2)(88 + 88 - 62) = 57
m<4 = 57
m<4 + m<5 + m<6 + m<3 = 180
57 + 31 + 44 + m<3 = 180
m<3 = 48
m<DGE + m<AGB + m<AGD = 180
m<DGE + 44 + 44 = 180
m<DGE = 92
m<DGE + m<4 + m<9 = 180
92 + 57 + m<9 = 180
m<9 = 31
m<4 + m<9 + m<8 + m<5 = 180
57 + 31 + m<8 + 31 = 180
m<8 = 61