Rewrite with only sin x and cos x
sin 3x - cos x
HELP!
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OpenStudy (muhammad_nauman_umair):
elaborate it
OpenStudy (anonymous):
2 sin x - sin^3 x - cos x
2 sin x cos^2 x + sin x - 2 sin^3 x - cos x
2 sin^3 x cos^4 x + 1
3 sin x cos x - sin^3 x - cos x
HERES THE ANSWER CHOICES (((((((:
OpenStudy (anonymous):
@Muhammad_Nauman_Umair
OpenStudy (anonymous):
@Zarkon help me please!
OpenStudy (anonymous):
or @saifoo.khan (:
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OpenStudy (saifoo.khan):
sin(2x) = 2sinxcosx
Now im stuck on how to use this for the left term in your problem.
OpenStudy (anonymous):
me too :(
OpenStudy (muhammad_nauman_umair):
either it is b or d option
OpenStudy (anonymous):
it was b thanks though
OpenStudy (saifoo.khan):
sin(3x) = sin(2x+x) = sin(2x) + sin(x)
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OpenStudy (raden):
sin(a+b) = sinacosb +cosasinb
OpenStudy (saifoo.khan):
^
OpenStudy (muhammad_nauman_umair):
option b is true
OpenStudy (muhammad_nauman_umair):
As
=Sin(2x+x)-Cosx
=Sin2xCosx+Cos2xSinx-Cosx
=(2 SinxCosx)Cosx+(1-2 Sin^2x)Sinx-Cosx
=2SinxCos^2x+Sinx-2Sin^3x-Cosx
OpenStudy (anonymous):
|dw:1355680197181:dw|
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OpenStudy (anonymous):
I got the answer guys don't worry! but thanks a ton(: