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How would I write (-4,3),(-7,-7) in standard form
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first, u can use the formula : (y-y1)/(y2-y1) = (x-x1)/(x2-x1)
thnk you, how would I write the equation in Ax+By=C?
in that form
have u got that equation ... show to me
I came up with y=-10/3X+16 1/3. is this correct?
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I'm being asked to put (-4,3), (-7,-7) and write it into standard form, having a hard time and was hoping that I finally figured it out
lol, well look this |dw:1355686000526:dw|
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