3½ / 3 1/6
Convert mixed fractions to improper fractions Then multiply the first fraction to the reciprocal of the second
\[\sqrt{\frac{ 9 }{ 16 }}\]
Problem: 3½ / 3 1/6 If this is "three and a half" divided by "three and one-sixth" Just remember that when dividing two fractions, you invert the second one and multiply. So you need to first convert the mixed fractions to improper ones. That gives you 7/2 and 19/6. Then invert the second one and multiply. Hope that helps!
Oh, is the problem the square root of 9 over 16? That's the same as the square root of 9 divided by the square root of 16. Can you figure that out?
Ways the answer
What
\[3 \frac{1}{2} = 3*\frac{2}{2} +\frac{1}{2} = \frac{6}{2} + \frac{1}{2} = 7/2\] \[3 \frac{1}{6} = 3*\frac{6}{6} +\frac{1}{6} = \frac{18}{6} + \frac{1}{6} = 19/6\] 7/2 * 6/19 and then...calculator time :P
Join our real-time social learning platform and learn together with your friends!