Question

What is 1+tan^2x=?

Answer 1

Nope other way around..

\[\tan^2 x + 1 = \sec^2x\]

Answer 2

I knew it i was making some mistake!

Answer 3

\[\tan^2x + 1 = \frac{\sin^2x}{\cos^2x} + \frac{\cos^2x}{\cos^2x} = \frac{1}{cos^2x} = \sec^2x\]

Answer 4

Thank you all! I got it!