Question

A potato is put into an oven that has been heated to 350°F. Its temperature as a function of time is given by T(t) = a(1 - e^-kt) + b. The potato was 50°F when it was first put into the oven.

When will the potato reach 150°F? Explain.

Answer 1

set \(T(t)=150\) and solve for \(t\) i.e. solve
\[a(1-e^{kt})+b=150\] which is rather difficult since you do not know \(a, b,\) or \(k\)

Answer 2

a=300

Answer 3

and i think b = 50*e^-kt

Answer 4

@satellite73