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|y|<2
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|y+4>|12
|p-6|>5
|2t+2/3|<4
To get rid of the absolute value you square both sides of the equation.
A child takes a nap averaging 3 hours and gets an average of 12 hours of sleep at night. Nap time and night time sleep can each vary by 30 minutes. What are the possible time lengths for the child's nap and night time sleep?
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|v|<2 -2<v<2 i think this is it
yeah i figured that out i need help with the others
but its absolute value?
When you have an equation with absolute value like |p-6|>5, all you have to do to get rid of it is square both sides. So it would turn into p-6>5^2. I messed it up sorry. The answer is p>11 or p<1
its fine thankss
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Ok, hope I helped :)
|dw:1355745792822:dw|
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