44% of US adults 18-34 years think that "Made In America" ads boost sales. Another poll show that 78% of adults in the 18-34 years category use social media online. Suppose that 85% of US adults in the 18-34 years category think that "Made in America" ads boost sales or use social media online.
If US adult in the 18-34 years category is randomly selected
A: What is the probability that the person thinks that " Made in America" ads boost sales and uses social media online?
B: What is the probability that made in America ads boost sales given that the person does not use social media onl

Question

44% of US adults 18-34 years think that "Made In America" ads boost sales. Another poll show that 78% of adults in the 18-34 years category use social media online. Suppose that 85% of US adults in the 18-34 years category think that "Made in America" ads boost sales or use social media online.
  If  US adult in the 18-34 years category is randomly selected
 A: What is the probability that the person thinks that " Made in America" ads boost sales and uses social media online?
 B: What is the probability that made in America ads boost sales given that the person does not use social media onl

anonymous · Answer

a venn diagram would help

anonymous · Answer

hello can you please answer my question @satellite73 i need help :(

anonymous · Answer

or use 
$$P(A\cup B)=P(A)+P(B)-P(A\cap B)$$ to solve for $P(A\cap B)$
$$P(A\cup B)=.85,P(A)=.44,P(B)=.78$$

anonymous · Answer

Ok so .44 + .78 - .85 = 1.22?

anonymous · Answer

sorry... (.44+.78 =1.22), then 1.22 - .85 =.37. Is that right?