Help!? AC is a diagonal of parallelogram ABCD. Which is the BCA? ( Picture Below!)
the measure of m<(40+BCA) and m<80 is called interior angle. the relation is the sum of them be 180 degrees. so, 40+m<BCA+80=180 solve for m<BCA
so I add 40?
hmmm.. let m<BCA is x. 40+m<BCA+80=180 40+x+80=180 120+x=180 subtract by 120 to both sides, gives 120+x-120=180-120 x=60
ohh you add then subtract from both side?
yes...
ok that explains things lol I've doing the wrong thing
I have one more question but it's a different type of angle so idk if I'm suppose ot use 180 still
nopes... :)
the pairs of m<FEH and 150 deg have relation "interior angle", so the sum of them must be 180. try it like ques before
*130 i meant, not 150
130 + m<FEH +180 130 subtracted form both sides is 50?
u are right
Yay! lol
there is typo there, it should writen 130+m<FEH=180 right ?
yes!
but ur solution it's okay :)
thank you!!
welcome
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