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OpenStudy (anonymous):
Help!? AC is a diagonal of parallelogram ABCD. Which is the BCA? ( Picture Below!)
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OpenStudy (raden):
the measure of m<(40+BCA) and m<80 is called interior angle.
the relation is the sum of them be 180 degrees.
so, 40+m<BCA+80=180
solve for m<BCA
OpenStudy (anonymous):
so I add 40?
OpenStudy (raden):
hmmm.. let m<BCA is x.
40+m<BCA+80=180
40+x+80=180
120+x=180
subtract by 120 to both sides, gives
120+x-120=180-120
x=60
OpenStudy (anonymous):
ohh you add then subtract from both side?
OpenStudy (raden):
yes...
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OpenStudy (anonymous):
ok that explains things lol I've doing the wrong thing
OpenStudy (anonymous):
I have one more question but it's a different type of angle so idk if I'm suppose ot use 180 still
OpenStudy (raden):
nopes... :)
OpenStudy (raden):
the pairs of m<FEH and 150 deg have relation "interior angle", so the sum of them must be 180. try it like ques before
OpenStudy (raden):
*130 i meant, not 150
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OpenStudy (anonymous):
130 + m<FEH +180
130 subtracted form both sides is 50?
OpenStudy (raden):
u are right
OpenStudy (anonymous):
Yay! lol
OpenStudy (raden):
there is typo there, it should writen 130+m<FEH=180 right ?
OpenStudy (anonymous):
yes!
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OpenStudy (raden):
but ur solution it's okay :)
OpenStudy (anonymous):
thank you!!
OpenStudy (raden):
welcome
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