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Mathematics 9 Online
OpenStudy (anonymous):

strontium has a half life of 23 years. what amount remains from a sample of 98mg after 115 years

OpenStudy (anonymous):

not sure but i got 3.06mg

OpenStudy (anonymous):

so u need to find k in \[1/2=e^{k*23}\], then plug k back into \[y=98e^{k*115}\] to find the answer.

OpenStudy (anonymous):

i dont get that.. istn't the half life formular a=i(1/2)^t/h?

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