Question

(3x-1)^2=25 solve by using the square root method

someone please help

Answer 1

the answer is false

Answer 2

\[\Large (3x-1)^2=25\]


\[\Large 3x-1=\pm\sqrt{25}\]


\[\Large 3x-1=\sqrt{25} \ \text{or} \ 3x-1=-\sqrt{25}\]


\[\Large 3x-1=5 \ \text{or} \ 3x-1=-5\]


\[\Large 3x=5+1 \ \text{or} \ 3x=-5+1\]


\[\Large 3x=6 \ \text{or} \ 3x=-4\]


\[\Large x=\frac{6}{3} \ \text{or} \ x=-\frac{4}{3}\]


\[\Large x=2 \ \text{or} \ x=-\frac{4}{3}\]

Answer 3

thank you so much!

Answer 4

yw