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determine the value of 10x^-3 when x=1/2
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10x^-3=10/(x^3) = 10/((1/2)^3)=10/(1/8)=80
thank you
I was assuming you did not leave off the parentheses like (10x)^-3
no there are no parentheses
i got 22 because 10 . 1/2 = 5 s^ = 25-3= 22
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how did u get 25
\[10\times x^{-3}\] where x=1/2 is the question Supergirl exponents before multiplication
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