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Mathematics 24 Online
OpenStudy (anonymous):

What is the derivative of f(x)= arctan(x^2)

OpenStudy (anonymous):

is arc meant to be a constant?

OpenStudy (anonymous):

it's tan^-1

OpenStudy (anonymous):

2x

OpenStudy (anonymous):

2x(\[[(2x)\sec^2(x^2)]/[\tan^2(x^2) +1]\]

OpenStudy (anonymous):

sorry answer is: [(2x)sec2(x2)]/[tan2(x2)+1] that make sense?

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