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Mathematics 21 Online
OpenStudy (anonymous):

(3/5x^-4yz^3)^-2

OpenStudy (anonymous):

\[(\frac{ 3 }{ 5 }x ^{-4}yz ^{3})^{-2}\] Use the power rule : \[(x^{y})^{z} = x^{yz}\] \[\frac{ 3 }{ 5 }x ^{8}y ^{-2} z ^{-6}\]

OpenStudy (anonymous):

Oh my bad you also have to do (3/5)^{-2)

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