Question

a graph of a parabola has a line of symmetry x=3 and contains points (1,0) and (4,-3). determinean equation for the parabola.

Answer 1

let the eq of parabola be (x-3)^2=A(y-B)
now we need to determine A and B

Answer 2

by puttin 1,0 we have AB =-4
and 1=-A(3+B)
solving the equation
B=-AB(3+B)
or B=+12 +4B or B=-4
and A=1
hence the reqd parabola is (x-3)^2=(y+4)