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Trigonometry
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Write the product (5 sin 3pi/4)(cos 7pi/4) as a sum or difference. How would I do this problem? I know the answer, but I don't know how to do it. The answer is: 5/2 (sin 5pi/2 - sin pi).
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use 2sinacosb =sin (a+b) - sin(a-b)
5/2 *2 sin 3pi/4)(cos 7pi/4
here a= 7pi/4 and b = 3pi/4 thus a+b=5pi/2 and a-b = 4pi/4=pi
Oh, okay. Thank you! :)
it should 2sinacosb =sin (a+b) + sin(a-b) @matricked
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@RadEn yup u r correct dear but the above also works as b>a
Thanks!!!! :D
sorry, @matricked i didny see, ur coment that a= 7pi/4 and b = 3pi/4 :)
no probs dear
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