Question

can somebody help me find the vertex and the x-intercepts of the quadratic equation.
y=1/2x^2-4

Answer 1

To find x-intercepts, put y=0 in the equation and solve for x.
Arrange the equation in this way:
2(y+4)=x^2 => vertex = (0,-4)

Answer 2

thank you so much!!!!!!!!!

Answer 3

welcome : )