Question

How do you integrate this??

(9x^2)/(1-x^3)^0.5

Answer 1

put 1-x^3 = u
du =.. ?

Answer 2

did u try that ?
u = 1-x^3
@mbhatti_95

Answer 3

yes I did but i keep getting stuck...
can you please help me with the solution?

Answer 4

sure.
what did u get du as ... ?
or which step are u stuck ?

Answer 5

du = -3x^2 dx

i am stuck after the integration when you have to give answer in terms of x... :S

Answer 6

so u could integrate properly, right ?
so u might have got -2/3 \(\sqrt u\)+c
now again put u=1-x^3
-2/3 \(\sqrt{1-x^3} +c \)

Answer 7

i keep getting -27( (1-x^3) - 2/3((1 - x^3)^3/2))

Answer 8

ok, after substitution did u get
\(\large \int \frac{-1}{3\sqrt u}du\)
?

Answer 9

allright pellet...
I realised my mistake... my bad sorry..
got it thanks a ton!!

Answer 10

good. welcome ^_^