How do you integrate this??

(9x^2)/(1-x^3)^0.5

Question

How do you integrate this??

(9x^2)/(1-x^3)^0.5

hartnn · Answer

put 1-x^3 = u
du =.. ?

hartnn · Answer

did u try that ? 
u = 1-x^3 
@mbhatti_95

anonymous · Answer

yes I did but i keep getting stuck...
can you please help me with the solution?

hartnn · Answer

sure.
what did u get du as ... ?
or which step are u stuck ?

anonymous · Answer

du = -3x^2 dx

i am stuck after the integration when you have to give answer in terms of x... :S

hartnn · Answer

so u could integrate properly, right ? 
so u might have got -2/3 $\sqrt u$+c
now again put u=1-x^3
-2/3 $\sqrt{1-x^3} +c $

anonymous · Answer

i keep getting  -27( (1-x^3)   -  2/3((1 - x^3)^3/2))

hartnn · Answer

ok, after substitution did u get 
$\large \int \frac{-1}{3\sqrt u}du$ 
?

anonymous · Answer

allright pellet...
I realised my mistake... my bad sorry..
got it thanks a ton!!

hartnn · Answer

good. welcome ^_^