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What is the measurement of each of the exterior angles of a regular pentagon? I cant find it anywhere!
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I'd use my logic for this one ;) Do you know that the sum of exterior angles in ANY polygon is \(360^{\circ}\)?
yeah I found that so the formula would be?
360 divided by 5 broseph
Okay, so a regular pentagon has five equal exterior angles. Then that means that one exterior angle is \(\dfrac{360}{5}\)
So the answer is 72?
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alright got it thanks!
Yes :) Good luck!
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