Question

what three consecutive odd numbers have a sum of 45?

Answer 1

x+x+1+x+2=45
3x+2=45
subtract 2 from each side
3x=43
divide each side by 3
x=14.3 or 14
1=14
plus 1
2=15
plus 2
3=17 < the answer

Answer 2

\[(x-2)+x+(x+2)=45\]\[3x=45\]\[x=15\]

so your numbers would be \(13,15,17\)