Question

(cos^2x + sin^2x)/(cosx+sinx)^2
Please simplify thanks

Answer 1

\[\text{ you should just \end up with} \to \frac{1}{\sin^2x + 2\sin x \cos x + \cos ^2 x}\]

Answer 2

you could also end up with:
1/1+2sinxcosx

Answer 3

\[\frac{ 1 }{ 1+2sinxcosx }\]

Answer 4

Or also with:
1/(sin2x+1)

Answer 5

:D

Answer 6

OR \(\dfrac{1}{2\cdot\cos^{2}\left(x-\dfrac{\pi}{4}\right)}\)