Given 2x+3y=18, find the equation of a line parallel to this line passing through (-3,-2)... I know that the slope is -2/3, in what formula do I plug in -3,-2 to get the answer/equation?

Question

anonymous · Answer

Use this equation
y-y1=m(x-x1)

y1 is given, its -2
x1 is given, its -3
m=the slope is given as -2/3
Lets plug in and work it out
y-(-2)=-2/3(x-(-3))
 y+2=-2/3(x+3) distribute -2/3
  y+2=-2/3x-2
    -2         -2
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y=-2/3x-4 ------> the equation