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Expand and simplify logarithm: \[\log_{3} 7x(1-x)\]
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\[\log_{3}7x(1-x)\] ?
yes i just edited the question as you were typing. that is the problem, yes.
Remember the log of a product rule \[\log_{3}7x+\log_{3}1-x\]
I am getting EITHER.... \[\log_{3} 7x + \log_{3} (1-x) OR \log_{3} 7 + \log_{3} x + \log_{3} (1-x) \]
This was also my first guess... but what about the "7x" ... isn't this also multiplication, which would expand it further?
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Yes i was gonna take it step by step, but you seem pretty good with these. Your second answer is what i would say
Got it! Thanks for the help and reassurance!!
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