Question

@ghazi

Answer 1

The second question has no options, it is a short response answer.

Answer 2

1

Answer 3

So how would I factor csc^2x - 1??

Answer 4

\[\csc^2 x -1 = {1 \over \sin^2x} - {\sin^2x \over \sin^2 x} ={ 1 - \sin^2x \over \sin^2 x} = {\cos^2x \over \sin^2 x} = \cot^2 x\]

Answer 5

Wow, you are amazing. Thank you so much!

Answer 6

it's a pleasure.

Answer 7

And thank you @ghazi! You both are amazing. :)

Answer 8

:)

Answer 9

sorry i didnt see the second one

Answer 10

It's okay, slaaibak helped me on that one. :)

Answer 11

By the way, I got everything correct on the test.

Answer 12

good job.