Straight line 4x-5y -40=0 is tangent to the ellipse find their meeting point (x^2)/50+(y^2)/32=1

Question

Straight line 4x-5y -40=0 is tangent to the ellipse find their meeting point                                                (x^2)/50+(y^2)/32=1

anonymous · Answer

have u tried pemdas?

anonymous · Answer

x^2+4y=36=>(x^2)/36+(4y^2)/36=36/36=>(x^2)/36+(y^2)/9=1=>(12;3)=(x;y)=>12x/36+3y/9=1=>x+y-108=0 we should use this xx/(a^2)+yy/(b^2)=1

anonymous · Answer

good job keep going ur on the right track

anonymous · Answer

Straight line 4x-5y -40=0 is tangent to the ellipse find their meeting point                                                (x^2)/50+(y^2)/32=1

anonymous · Answer

and then...

anonymous · Answer

|dw:1356029613810:dw|The elipse equation is$$x^2/36+y^2/20=1$$find the rectangle surface MNPQ