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find the value of k so that the line has slope m: 6x+ky = 10 and m=-2 k=-8 k=4 k=3 k=-3
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ky = -6x + 10 -> y = (-6/k)x + 10/k So, -6/k = -2 -> k = 3
thanks! what about (k+1)x+2y=6 and m=-(1/3)
2y = -(k + 1)x + 6 -> y = -[(k + 1)/2]x + 3 -[(k + 1)/2] = -(1/3) -> [(k + 1)/2] = (1/3) k + 1 = 2/3 -> k = -1/3
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