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Solve. x^2 + 8x = 24 –4 ± 2 √ 2 –4 ± 2√ 10 –4 ± 2√ 5 –4 ± 2√ 7
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would it be the 2nd one?
Move the constant term to the LHS and use the quadratic formula, or complete the square.
I know how to do it just looking for someone to check my answer and make sure its correct
\[x^2 + 8x = 24 \implies x^2 + 8x +16=24+16 \implies (x+4)^2=40\] \[\implies x+4= \pm \sqrt{40} \implies x=4 \pm \sqrt{40}\]
\[4 \pm \sqrt{40} =4 \pm 2 \sqrt {10}\]
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Do math every day.
ok so I was correct then :) thank you
No sweat.
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