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how do you find sin^2(135 degrees)? trig final tomorrow! please help :(
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135 degrees is one of your special angles, having trouble remembering that one? :)
apparently...i really have no clue what to do
\[\sqrt{2}/2 for \sin\]
135 degree equal to 3pi/4
My friend found that it equaled 1/2...and i believe this is correct i just don't understand how he got it. can someone explain?
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it is in this form\[\sin ^{2}(3\pi/4)\]
the answer with calculator is 0.08
sin²(135º) = sin(135º)·sin(135º)
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