Question

27^-(2/3)

Answer 1

0.11111

Answer 2

\[27^{-2/3} = \sqrt[3]{27^{-2}}= \sqrt[3]{\frac{1}{27^2}}=\sqrt[3]{\frac{1}{9^{(3\dot\ 2)}}}=\sqrt[3]{\frac{1}{9^{(2 \dot\ 3)}}}=\sqrt[3]{\frac{1^3}{81^3}}=\sqrt[3]{\left(\frac{1}{81}\right)^3}=\frac{1}{81}\]

Answer 3

Hero, I'm sorry.. I didn't see it. Thank youu!

Answer 4

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