Question

help pls
int main()
{
int n;
printf("n="); scanf("%lf",n);
for(i=0;;i++);
if(i=10)break;
printf("%d",i,i*i);
return 0;
}
can someone help me correct this code. too many mistakes in this code. tried countless times but failed :(

Answer 1

Firstly you need to add an #include directive for stdio.h. Aside from that, you need to use the proper format specifier in scanf... %lf corresponds to reading a double, rather than an int; maybe you meant %d? Your loop is tight and doesn't do anything since you have a semicolon right after the for statement; even if the loop were correct, your if statement should be eliminated in favor of a loop condition i.e. for (i = 0; i < 10; ++i)... note that your if statement is broken anyways, since if (i = 10) is not the same thing as if (i == 10) -- the latter compares i and 10 while the former reassigns i and thus will always take the branch since (i = 10) evaluates to 10 which is non-zero. Did you even mean to use 10, rather than n, here? Your final printf call is probably incorrect, too, since you specify two arguments (i and i * i) while only formatting the first, and there's no white space for delimiting. You don't need to return 0 since main by default returns 0 according to the C standard, and you should really use braces and new lines to make teh code less cluttered. Here's a corrected form of your code:

#include <stdio.h>

int main() {
int n;
printf("n=");
scanf("%d", &n);

int i;
for (i = 0; i < n; ++i) {
printf("%d %d\n", i, i * i);
}
}